In this exercise none of the solvents in your factory will dissolve  rubber.  However you may mix two solvents together to make a solvent blend which will do the job.  For example, if the solubility area for rubber is halfway between the intersections of the solubility parameters (P & H values) for two solvents, then a 50/50 mix of those two solvents will dissolve rubber.

Which of the solvents listed in the far right column can be mixed with Toluene in a 20/80 mix to produce a solvent blend that will dissolve rubber?


Benzene  - P=0.0  H=2.0
Methanol - P=12.3 H=22.3
Ethylene dichloride - P=7.4 H=4.1
Ethanol - P=8.8 H=19.4
Acetone - P=10.4 H=7.0
Methyl chloride - P=6.1 H=3.9
Tetrahydrofuran - P=5.7 H=8.0
Toluene - P=1.4 H=2.0
Xylene - P=1.0 H=3.1
Nitromethane - P=18.8 H=5.1
Methyl ethyl ketone - P=9.0 H=5.1
Dimethylformamide - P=13.7 H=11.3

Indicate your choice by clicking on the name of the solvent you want to use.

(You may print this page to make your plot on paper.)


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